integral of 8x^9-3x^6+12x^3

Lösung

\int 8 x^{9} - 3 x^{6} + 12 x^{3} d x

\frac{4 x ^{10}}{5} - \frac{3 x ^{7}}{7} + 3 x^{4} + C

Schritte zur Lösung

\int 8 x^{9} - 3 x^{6} + 12 x^{3} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 8 x^{9} d x - \int 3 x^{6} d x + \int 12 x^{3} d x

\int 8 x^{9} d x = \frac{4 x ^{10}}{5}

\int 3 x^{6} d x = \frac{3 x ^{7}}{7}

\int 12 x^{3} d x = 3 x^{4}

= \frac{4 x ^{10}}{5} - \frac{3 x ^{7}}{7} + 3 x^{4}

Füge eine Konstante zur Lösung hinzu

= \frac{4 x ^{10}}{5} - \frac{3 x ^{7}}{7} + 3 x^{4} + C

\frac{\partial}{\partial x} ((x - 1)^{\frac{2}{3}} (y - 4))

\frac{d}{d y} (y ln (y))

t an g e n t f (x) = 6 e^{x} cos (x), (0, 6)

\frac{\partial}{\partial x} (cos (x^{2} + x y))

n = 3 \sum \infty \frac{6}{n ^{2} - 1}