What is the derivative of f(x)=(4x-1)/x ?

The derivative of f(x)=(4x-1)/x is 1/(x^2)

What is the first derivative of f(x)=(4x-1)/x ?

The first derivative of f(x)=(4x-1)/x is 1/(x^2)

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derivative of

f (x) = \frac{4 x - 1}{x}

\frac{1}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{4 x - 1}{x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 4 x - 1 ) x - \frac{d x}{d x} ( 4 x - 1 )}{x ^{2}}

\frac{d}{d x} (4 x - 1) = 4

\frac{d x}{d x} = 1

= \frac{4 x - 1 \cdot ( 4 x - 1 )}{x ^{2}}

Simplify

= \frac{1}{x ^{2}}

d er i v a t i v e 2^{z}

d er i v a t i v e y = sin (x^{- 1})

d er i v a t i v e x^{2} cos (lo g_{10} (x))

\frac{d}{d t} (2 t - 2)

d er i v a t i v e \frac{2 x - 4}{x ^{\frac{1}{2}}}

What is the derivative of f(x)=(4x-1)/x ?
The derivative of f(x)=(4x-1)/x is 1/(x^2)
What is the first derivative of f(x)=(4x-1)/x ?
The first derivative of f(x)=(4x-1)/x is 1/(x^2)