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Beliebt Rechnen >

y^{''}+y^'=1,y^1(0)=1

Lösung

y^{^{''}} + y^{^{'}} = 1, y^{1} (0) = 1

Lösung

y = c_{1} + c_{2} e^{- t} + t

Schritte zur Lösung

y^{''} (t) + y^{'} (t) = 1

Solve linear ODE:

y = c_{1} + c_{2} e^{- t} + t

y = c_{1} + c_{2} e^{- t} + t

Graph

Beliebte Beispiele

y^{''}+2y^'-3y=sin(t)

y^{^{''}} + 2 y^{^{'}} - 3 y = sin (t)

(d^2-2d+2)y=x^2e^3x

(d^{2} - 2 d + 2) y = x^{2} e^{3} x

y^{''}+y^'-2y=8sin(2x)

y^{^{''}} + y^{^{'}} - 2 y = 8 sin (2 x)

(d^2+2d+1)y=cos^2(x)

(d^{2} + 2 d + 1) y = cos^{2} (x)

(d^2+5d+6)y=e^{-2}xsin^2(x)

(d^{2} + 5 d + 6) y = e^{- 2} x sin^{2} (x)