(d^2-2d+5)y=5

Lösung

(d^{2} - 2 d + 5) y = 5

y = e^{x} (c_{1} cos (2 x) + c_{2} sin (2 x)) + 1

Schritte zur Lösung

(d^{2} - 2 d + 5) y = 5

Solve linear ODE:

y = e^{x} (c_{1} cos (2 x) + c_{2} sin (2 x)) + 1

y = e^{x} (c_{1} cos (2 x) + c_{2} sin (2 x)) + 1

d \cdot g (x) = 2 x + 1

4 y^{^{''}} + 4 y^{^{'}} + y = cos (t)

y^{^{''}} + 3 y^{^{'}} + 2 y = 4 x + 3

(d^{2} + d - 2) y = lo g_{6} (x)

(d^{2} + 5 d + 6) \cdot y = e^{x}