What is the integral of (6x^{1/5}+10) ?

The integral of (6x^{1/5}+10) is 5x^{6/5}+10x+C

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integral of (6x^{1/5}+10)

\int (6 x^{\frac{1}{5}} + 10) d x

5 x^{\frac{6}{5}} + 10 x + C

Solution steps

\int 6 x^{\frac{1}{5}} + 10 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 6 x^{\frac{1}{5}} d x + \int 10 d x

\int 6 x^{\frac{1}{5}} d x = 5 x^{\frac{6}{5}}

\int 10 d x = 10 x

= 5 x^{\frac{6}{5}} + 10 x

Add a constant to the solution

= 5 x^{\frac{6}{5}} + 10 x + C

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What is the integral of (6x^{1/5}+10) ?
The integral of (6x^{1/5}+10) is 5x^{6/5}+10x+C