limit as x approaches-8 of (x+2)/(x+8)

Lösung

x \to - 8 lim (\frac{x + 2}{x + 8})

divergiert

Schritte zur Lösung

x \to - 8 lim (\frac{x + 2}{x + 8})

Wenn

x \to a - lim f (x) \neq = x \to a + lim f (x)

dann gibt es keine Grenze

x \to - 8 + lim (\frac{x + 2}{x + 8}) = - \infty

x \to - 8 - lim (\frac{x + 2}{x + 8}) = \infty

= divergiert

x \to 2 lim (2 x^{2} + 7 x - 1)

x \to - 3 + lim (2 x^{2} - 6)

\frac{\partial}{\partial x} (x^{m})

\frac{\partial}{\partial x} (\frac{( 5 x + 3 )}{( y - 2 )})

x \to 5 lim (\frac{2 ^{x} - 32}{x - 5})