What is the integral from 0 to 2pi of 3sin(x/2) ?

The integral from 0 to 2pi of 3sin(x/2) is 12

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integral from 0 to 2pi of 3sin(x/2)

\int_{0}^{2 π} 3 sin (\frac{x}{2}) d x

12

Solution steps

\int_{0}^{2 π} 3 sin (\frac{x}{2}) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{0}^{2 π} sin (\frac{x}{2}) d x

Apply u-substitution

: \int_{0}^{π} sin (u) \cdot 2 d u

= 3 \cdot \int_{0}^{π} sin (u) \cdot 2 d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot 2 \cdot \int_{0}^{π} sin (u) d u

Use the common integral:

\int sin (u) d u = - cos (u)

= 3 \cdot 2 [- cos (u)]_{0}^{π}

Simplify

= 6 [- cos (u)]_{0}^{π}

Compute the boundaries:

2

= 6 \cdot 2

Simplify

= 12

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What is the integral from 0 to 2pi of 3sin(x/2) ?
The integral from 0 to 2pi of 3sin(x/2) is 12