integral from 4 to 12 of 1/8

Lösung

\int_{4}^{12} \frac{1}{8} d x

1

Schritte zur Lösung

\int_{4}^{12} \frac{1}{8} d x

Integral einer Konstanten :

\int a d x = a x

= [\frac{1}{8} x]_{4}^{12}

Berechne die Grenzen:

1

= 1

\int_{0}^{1} (6 - 9 x)^{2} d x

\int_{2}^{3} \frac{x ^{5} + 1}{x ^{6} + 6 x} d x

\int_{- 1}^{1} k (3 - x^{2}) d x

\int_{0}^{1} x^{8} \cdot e^{- x} d x

\int_{0}^{b} t e^{- s t} d t