integral from 1 to 3 of x(sqrt(x)+1)

Lösung

\int_{1}^{3} x (x + 1) d x

\frac{18 3 - 2}{5} + 4

Dezimale

9.83538 \dots

Schritte zur Lösung

\int_{1}^{3} x (x + 1) d x

Multipliziere aus

x (x + 1) : x^{\frac{3}{2}} + x

= \int_{1}^{3} x^{\frac{3}{2}} + x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{3} x^{\frac{3}{2}} d x + \int_{1}^{3} x d x

\int_{1}^{3} x^{\frac{3}{2}} d x = \frac{18 3 - 2}{5}

\int_{1}^{3} x d x = 4

= \frac{18 3 - 2}{5} + 4

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