integral from 0 to 1 of (1-e^2)^{1/2}

Lösung

\int_{0}^{1} (1 - e^{2})^{\frac{1}{2}} d x

i (e^{2} - 1)^{\frac{1}{2}}

Schritte zur Lösung

\int_{0}^{1} (1 - e^{2})^{\frac{1}{2}} d x

Integral einer Konstanten :

\int a d x = a x

= [(1 - e^{2})^{\frac{1}{2}} x]_{0}^{1}

Wende imaginäre Zahlenregel an:

- a = i a

= [i (- 1 + e^{2})^{\frac{1}{2}} x]_{0}^{1}

Berechne die Grenzen:

i (e^{2} - 1)^{\frac{1}{2}}

= i (e^{2} - 1)^{\frac{1}{2}}

\int_{0}^{2} (\frac{1}{1 + x ^{2}})^{2} d x

\int_{- π}^{π} (sin (x))^{2} d x

\int_{0}^{1} 1 + 2 t^{2} + t^{4} d t

\int_{e}^{e^{2}} (ln (x))^{2} (\frac{1}{x}) d x

\int_{- 1}^{1} \frac{x + 1}{x - 1} d x