integral from 0 to 2 of 1/6 x

Lösung

\int_{0}^{2} \frac{1}{6} x d x

\frac{1}{3}

Dezimale

0.33333 \dots

Schritte zur Lösung

\int_{0}^{2} \frac{1}{6} x d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{6} \cdot \int_{0}^{2} x d x

Wende die Potenzregel an

= \frac{1}{6} [\frac{x ^{2}}{2}]_{0}^{2}

Berechne die Grenzen:

2

= \frac{1}{6} \cdot 2

Vereinfache

= \frac{1}{3}

\int_{1}^{4} \frac{1}{6} (x - 1) d x

\int_{25}^{40} \frac{1}{15} x^{2} d x

\int_{- 1}^{1} (- 1 + 2 t^{2})^{3} d t

\int_{1}^{e} \frac{( ln ( t ) ) ^{2}}{t} d t

\int_{- 2}^{1} x (2 - x^{2} - x) d x