integral from-1 to 1 of (x-y)

Lösung

\int_{- 1}^{1} (x - y) d y

2 x

Schritte zur Lösung

\int_{- 1}^{1} x - y d y

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} x d y - \int_{- 1}^{1} y d y

\int_{- 1}^{1} x d y = 2 x

\int_{- 1}^{1} y d y = 0

= 2 x - 0

Vereinfache

= 2 x

\int_{1}^{2} \frac{x + 2}{8} d x

\int_{- 3}^{3} (2 + 9 - x^{2}) d x

\int_{0}^{6} 2 π y (36 - y^{2}) d y

\int_{2}^{4} \frac{4}{x} d x

\int_{0}^{1} sech^{2} (5 x) d x