integral from 0 to 3 of x/(1+x^4)

Lösung

\int_{0}^{3} \frac{x}{1 + x ^{4}} d x

\frac{1}{2} arctan (9)

Dezimale

0.73006 \dots

Schritte zur Lösung

\int_{0}^{3} \frac{x}{1 + x ^{4}} d x

Berechne das unbestimmte Integral:

\int \frac{x}{1 + x ^{4}} d x = \frac{1}{2} arctan (x^{2}) + C

Berechne die Grenzen:

\int_{0}^{3} \frac{x}{1 + x ^{4}} d x = \frac{1}{2} arctan (9) - 0

= \frac{1}{2} arctan (9) - 0

Vereinfache

= \frac{1}{2} arctan (9)

\int_{0}^{t} \frac{1}{e ^{x}} d x

\int_{0}^{e} \frac{2}{e + 2 x} d x

\int_{1}^{2} \frac{x}{y} d y

\int_{- 6}^{- 1} - x^{2} - 7 x - 6 d x

\int_{- \frac{π}{3}}^{\frac{π}{2}} cos (2 x) d x