ja

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

人気のある微分積分 >

integral from 0 to 1-y of (1-y^2)

解

\int_{0}^{1 - y} (1 - y^{2}) d y

解

- y + 1 - \frac{( - y + 1 ) ^{3}}{3}

解答ステップ

\int_{0}^{1 - y} 1 - y^{2} d y

総和規則を適用する:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1 - y} 1 d y - \int_{0}^{1 - y} y^{2} d y

\int_{0}^{1 - y} 1 d y = - y + 1

\int_{0}^{1 - y} y^{2} d y = \frac{( - y + 1 ) ^{3}}{3}

= - y + 1 - \frac{( - y + 1 ) ^{3}}{3}

人気の例

integral from 0 to 5 of 300e^{0.2x-1}

\int_{0}^{5} 300 e^{0.2 x - 1} d x

integral from 1 to 4 of 3/(2x+1)+cos(2x)

\int_{1}^{4} \frac{3}{2 x + 1} + cos (2 x) d x

integral from 1 to 2 of (e^x+1/x)

\int_{1}^{2} (e^{x} + \frac{1}{x}) d x

integral from-1 to x of 1/(1+t^2)

\int_{- 1}^{x} \frac{1}{1 + t ^{2}} d t

integral from 0 to x of te^{t^2}

\int_{0}^{x} t e^{t^{2}} d t