integral from-1 to-2 of f(t)

Lösung

\int_{- 1}^{- 2} f (t)

\frac{3 t}{2}

Schritte zur Lösung

\int_{- 1}^{- 2} f t df

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{- 2}^{- 1} t fdf

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - t \cdot \int_{- 2}^{- 1} fdf

Wende die Potenzregel an

= - t [\frac{f ^{2}}{2}]_{- 2}^{- 1}

Berechne die Grenzen:

- \frac{3}{2}

= - t (- \frac{3}{2})

Vereinfache

= \frac{3 t}{2}

\int_{0}^{1} [x^{\frac{1}{n}} - x] d x

\int_{0}^{2} x^{2} 4 x^{2} + 1 d x

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\int_{1}^{3} \frac{x}{x ^{2} - 4} d x