integral from-1 to 2 of ((2-x^2)-(-x))

解答

\int_{- 1}^{2} ((2 - x^{2}) - (- x)) d x

\frac{9}{2}

十进制

4.5

求解步骤

\int_{- 1}^{2} 2 - x^{2} - (- x) d x

化简

= \int_{- 1}^{2} 2 - x^{2} + x d x

使用积分加法定则:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{2} 2 d x - \int_{- 1}^{2} x^{2} d x + \int_{- 1}^{2} x d x

\int_{- 1}^{2} 2 d x = 6

\int_{- 1}^{2} x^{2} d x = 3

\int_{- 1}^{2} x d x = \frac{3}{2}

= 6 - 3 + \frac{3}{2}

化简

6 - 3 + \frac{3}{2} : \frac{9}{2}

= \frac{9}{2}

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