integral from 6 to infinity of 2x^{-3}

解答

\int_{6}^{\infty} 2 x^{- 3} d x

\frac{1}{36}

十进制

0.02777 \dots

求解步骤

\int_{6}^{\infty} 2 x^{- 3} d x

计算不定积分:

\int 2 x^{- 3} d x = - \frac{1}{x ^{2}} + C

带入上下限计算后得:

\int_{6}^{\infty} 2 x^{- 3} d x = 0 - (- \frac{1}{36})

= 0 - (- \frac{1}{36})

化简

= \frac{1}{36}

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