integral from-1 to 8 of \sqrt[3]{x^2}

Lösung

\int_{- 1}^{8} 3 x^{2} d x

\frac{99}{5}

Dezimale

19.8

Schritte zur Lösung

\int_{- 1}^{8} 3 x^{2} d x

3 x^{2} = x^{\frac{2}{3}},

angenommen

x \geq 0

= \int_{- 1}^{8} x^{\frac{2}{3}} d x

Wende die Potenzregel an

= [\frac{3}{5} x^{\frac{5}{3}}]_{- 1}^{8}

Berechne die Grenzen:

\frac{99}{5}

= \frac{99}{5}

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