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人気のある微分積分 >

integral from 0 to 1 of (x^3+4x)

解

\int_{0}^{1} (x^{3} + 4 x) d x

解

\frac{9}{4}

+1

十進法表記

2.25

解答ステップ

\int_{0}^{1} x^{3} + 4 x d x

総和規則を適用する:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} x^{3} d x + \int_{0}^{1} 4 x d x

\int_{0}^{1} x^{3} d x = \frac{1}{4}

\int_{0}^{1} 4 x d x = 2

= \frac{1}{4} + 2

簡素化

\frac{1}{4} + 2 : \frac{9}{4}

= \frac{9}{4}

グラフ

人気の例

integral from 1 to 2 of 1/(y+4)

\int_{1}^{2} \frac{1}{y + 4} d y

integral from 1 to 2 of 3x-x^2+2

\int_{1}^{2} 3 x - x^{2} + 2 d x

integral from 0 to 1 of sqrt(2+1/(4x))

\int_{0}^{1} 2 + \frac{1}{4 x} d x

integral from 0 to 1 of cos(θ)

\int_{0}^{1} cos (θ) d θ

integral from 0 to infinity of 4x

\int_{0}^{\infty} 4 x d x