integral from 0 to 1 of sqrt(1)

Lösung

\int_{0}^{1} 1

1

Schritte zur Lösung

\int_{0}^{1} 1 d x

Integral einer Konstanten :

\int a d x = a x

= [1 x]_{0}^{1}

Vereinfache

= [x]_{0}^{1}

Berechne die Grenzen:

1

= 1

\int_{1}^{2} (2 - 6 y^{2}) d y

\int_{2}^{5} 2 π y (5 - y) d y

\int_{0}^{4} \frac{x ^{2}}{16} d x

\int_{1}^{2} - \frac{1}{x} d x

\int_{1}^{2} x^{2} - \frac{1}{4 x ^{2}} d x