What is the limit as x approaches-4+of sqrt(x^2-16) ?

The limit as x approaches-4+of sqrt(x^2-16) is 0

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limit as x approaches-4+of sqrt(x^2-16)

x \to - 4 + lim (x^{2} - 16)

0

Solution steps

x \to - 4 + lim (x^{2} - 16)

Plug in the value

x = - 4

= (- 4)^{2} - 16

Simplify

(- 4)^{2} - 16 : 0

= 0

x \to - 3 lim (x^{3} - 2 x + 11)

x \to 0 lim (\frac{x}{3 x ^{2} + 1})

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x \to 4 lim (x (4))

x \to 0 lim (sin (\frac{2 x}{x}))

What is the limit as x approaches-4+of sqrt(x^2-16) ?
The limit as x approaches-4+of sqrt(x^2-16) is 0