limit as t approaches 0 of (sin^2(t))/t

Lösung

t \to 0 lim (\frac{sin ^{2} ( t )}{t})

0

Schritte zur Lösung

t \to 0 lim (\frac{sin ^{2} ( t )}{t})

Wende das L'Hopital Theorem an

= t \to 0 lim (\frac{sin ( 2 t )}{1})

Setze den Wert

t = 0

ein

= \frac{sin ( 2 \cdot 0 )}{1}

Vereinfache

\frac{sin ( 2 \cdot 0 )}{1} : 0

= 0

x \to - 1 lim (8 x^{2} + 7 x - 3)

x \to 2 lim (\frac{( x ^{3} - 3 x ^{2} + 4 )}{x ^{3} - 7 x ^{2} + 16 x - 12})

x \to - \infty lim (e^{x t})

x \to \infty lim (3 + \frac{6}{x})

b \to \infty lim (sin (b))