sum from n=0 to infinity of n/(5n^2+1)

Lösung

n = 0 \sum \infty \frac{n}{5 n ^{2} + 1}

divergiert

Schritte zur Lösung

n = 0 \sum \infty \frac{n}{5 n ^{2} + 1}

Reihenintegraltest anwenden:

divergiert

= divergiert

n = 1 \sum \infty \frac{n}{n ^{3} + n + 1}

n = 0 \sum \infty (\frac{4 π}{e})^{n}

n = 0 \sum \infty (\frac{8}{7})^{n}

x = 0 \sum \infty \frac{x}{2 x + 1}

n = 0 \sum \infty arctan (\frac{π}{4})