sum from n=0 to infinity of (4/11)^n

Lösung

n = 0 \sum \infty (\frac{4}{11})^{n}

\frac{11}{7}

Dezimale

1.57142 \dots

Schritte zur Lösung

n = 0 \sum \infty (\frac{4}{11})^{n}

Geometrischen Test der Reihe anwenden:

\frac{11}{7}

= \frac{11}{7}

j = 1 \sum \infty 2 (- \frac{3}{5})^{j}

n = 1 \sum \infty - \frac{1}{1 0 ^{n}}

n = 1 \sum \infty 4 (\frac{π}{4})^{n}

n = 1 \sum \infty n! e^{- 2 n}

n = 1 \sum \infty 3 (\frac{1}{4})^{n}