sum from n=0 to infinity of (1/23)^n

Lösung

n = 0 \sum \infty (\frac{1}{23})^{n}

\frac{23}{22}

Dezimale

1.04545 \dots

Schritte zur Lösung

n = 0 \sum \infty (\frac{1}{23})^{n}

Geometrischen Test der Reihe anwenden:

\frac{23}{22}

= \frac{23}{22}

n = 1 \sum \infty (\frac{n}{e})^{n}

n = 1 \sum \infty 3 (\frac{2}{5})^{n}

n = 1 \sum \infty \frac{ln ( n ^{4} )}{n}

n = 2 \sum \infty \frac{5}{n ( n + 2 )}

n = 1 \sum \infty \frac{1}{3 ^{n} - n}