What is the sum from n=3 to infinity of (4^n)/(3^n) ?

The sum from n=3 to infinity of (4^n)/(3^n) is diverges

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sum from n=3 to infinity of (4^n)/(3^n)

n = 3 \sum \infty \frac{4 ^{n}}{3 ^{n}}

diverges

Solution steps

n = 3 \sum \infty \frac{4 ^{n}}{3 ^{n}}

Apply Series Ratio Test:

diverges

= diverges

n = 1 \sum \infty sec (n)

n = 0 \sum \infty \frac{2}{5}

n = 0 \sum \infty \frac{2}{3 + n}

n = 1 \sum \infty \frac{2}{7 ^{n} + 1}

n = 0 \sum \infty 10 \cdot 9.14

What is the sum from n=3 to infinity of (4^n)/(3^n) ?
The sum from n=3 to infinity of (4^n)/(3^n) is diverges