sum from x=1 to infinity of (x+2)/(x+1)

Lösung

x = 1 \sum \infty \frac{x + 2}{x + 1}

divergiert

Schritte zur Lösung

n = 1 \sum \infty \frac{n + 2}{n + 1}

Seriendivergenztest anwenden:

divergiert

= divergiert

n = 1 \sum \infty (\frac{1}{3})^{2 n}

n = 0 \sum \infty \frac{cos ( πn )}{5}

n = 11 \sum \infty \frac{17}{3 ^{n}}

n = 0 \sum \infty sec (\frac{1}{n ^{2}})

n = 0 \sum \infty n^{2} e^{n^{3}}