What is the sum from n=0 to infinity of 1-1/(n^2) ?

The sum from n=0 to infinity of 1-1/(n^2) is diverges

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sum from n=0 to infinity of 1-1/(n^2)

n = 0 \sum \infty 1 - \frac{1}{n ^{2}}

diverges

Solution steps

n = 1 \sum \infty 1 - \frac{1}{n ^{2}}

Apply Series Divergence Test:

diverges

= diverges

n = 0 \sum \infty \frac{8}{( - 3 ) ^{n}}

n = 1 \sum \infty n \cdot 0. 5^{n}

n = 1.3 \sum \infty e^{- 1.8 n}

n = 1 \sum \infty \frac{1}{( 4 n ) ^{5}}

n = 1 \sum \infty \frac{n}{1 ^{n}}

What is the sum from n=0 to infinity of 1-1/(n^2) ?
The sum from n=0 to infinity of 1-1/(n^2) is diverges