4(dy)/(dx)=1+2x+3y^2+6xy^2

Lösung

4 \frac{d y}{d x} = 1 + 2 x + 3 y^{2} + 6 x y^{2}

y = \frac{tan ( \frac{3 ( x ^{2} + x + c _{1} )}{4} )}{3}

Schritte zur Lösung

4 \frac{d y}{d x} = 1 + 2 x + 3 y^{2} + 6 x y^{2}

Solve separable ODE:

y = \frac{tan ( \frac{3 ( x ^{2} + x + c _{1} )}{4} )}{3}

y = \frac{tan ( \frac{3 ( x ^{2} + x + c _{1} )}{4} )}{3}

y^{^{'}} = 2 y - 5

\frac{d y}{d t} + 3 y = 7, y (0) = 1

e^{x} \cdot \frac{d y}{d x} = 1 + y^{2}

y^{^{'}} + x^{2} y = 0

\frac{d y}{d x} = e^{- y} (2 x - 4), y (5) = 0