y^'= x/(2y)

Lösung

y^{^{'}} = \frac{x}{2 y}

y = \frac{x ^{2}}{2} + c_{1}, y = - \frac{x ^{2}}{2} + c_{1}

Schritte zur Lösung

y^{'} (x) = \frac{x}{2 y}

Solve separable ODE:

y = \frac{x ^{2}}{2} + c_{1}, y = - \frac{x ^{2}}{2} + c_{1}

y = \frac{x ^{2}}{2} + c_{1}, y = - \frac{x ^{2}}{2} + c_{1}

(1 + y^{2}) cos (x) d x - \frac{1}{x} d y = 0, y (0) = \frac{π}{4}

y^{^{'}} = x^{3} y^{3}

d x - (8 x y + 3 y) d y = 0

\frac{d y}{d x} = \frac{y}{2 x + 1}

y^{^{'}} - a^{2} k y + b^{2} = 0