y^'+y= y/x

Lösung

y^{^{'}} + y = \frac{y}{x}

y = e^{- x + c_{1}} x

Schritte zur Lösung

y^{'} (x) + y = \frac{y}{x}

Solve separable ODE:

y = e^{- x + c_{1}} x

y = e^{- x + c_{1}} x

\frac{d y}{d x} = a - b \cdot y

\frac{d y}{d x} - 3 y = 12

(1 + y) y^{^{'}} = y

x^{^{'}} - 2 x = 4

x d x + (sin (y) + x^{2} sin (y)) d y = 0