y^'+y=y^6

Lösung

y^{^{'}} + y = y^{6}

y = 5 \frac{1}{1 - e ^{5 (t + c_{1})}}

Schritte zur Lösung

y^{'} (t) + y = y^{6}

Solve separable ODE:

y = 5 \frac{1}{1 - e ^{5 (t + c_{1})}}

y = 5 \frac{1}{1 - e ^{5 (t + c_{1})}}

y^{^{'}} = \frac{11 x ^{2} - 1}{11 + 9 y}

(x^{2} + 1) d x - 3 y d y = 0

e^{x + y} \frac{d x}{d y} = x

\frac{d q}{d t} = k q (t)^{2}

y^{^{'}} = \frac{e ^{- x}}{sin ( y )}, y (1) = 0