x*y^'+y=0

Lösung

x \cdot y^{^{'}} + y = 0

y = \frac{c _{1}}{x}

Schritte zur Lösung

x \cdot y^{'} (x) + y = 0

Solve separable ODE:

y = \frac{c _{1}}{x}

y = \frac{c _{1}}{x}

y^{^{'}} = y - y^{2}, y (- 1) = 2

(3 x^{2} + 2)^{3} y^{^{'}} - x y^{2} = 0

y^{^{'}} = \frac{5 ( 1 + x )}{x y}

x^{2} \frac{d y}{d x} + 3 x y = x

\frac{d y}{d x} = 12 x^{3} y, y (0) = 2