(1+x^2)y^'=sin(y)

Lösung

(1 + x^{2}) y^{^{'}} = sin (y)

y = 2 arctan (e^{a r c t a n (x) + c_{1}}) + 2 πn

Schritte zur Lösung

(1 + x^{2}) y^{'} (x) = sin (y)

Solve separable ODE:

y = 2 arctan (e^{a r c t a n (x) + c_{1}}) + 2 πn

y = 2 arctan (e^{a r c t a n (x) + c_{1}}) + 2 πn

\frac{3 d y}{2 d x} + \frac{4 x + 2 x y ^{2}}{2 y + x ^{2} y} = 0

y^{^{'}} - y = 3, y (0) = 0

y^{^{'}} = \frac{x}{3 - y}, y (2) = 0

\frac{d y}{d x} y = x^{l n (x)}

x^{^{'}} = a x