(x-2)y^'+y=0

Lösung

(x - 2) y^{^{'}} + y = 0

y = \frac{c _{1}}{x - 2}

Schritte zur Lösung

(x - 2) y^{'} (x) + y = 0

Solve separable ODE:

y = \frac{c _{1}}{x - 2}

y = \frac{c _{1}}{x - 2}

\frac{d y}{d x} = e^{- y}

y^{^{'}} = 3 x e^{y}

\frac{d y}{d x} = 10 x^{9} y

y^{^{'}} = x y^{3} (1 + x^{2})^{\frac{- 1}{2}}

\frac{x ^{2} + 2 x}{x + 1} y^{^{'}} - \frac{1}{y ^{3}} = 0