(x+2)y^'=3y

Lösung

(x + 2) y^{^{'}} = 3 y

y = e^{c_{1}} x^{3} + 6 e^{c_{1}} x^{2} + 12 e^{c_{1}} x + 8 e^{c_{1}}

Schritte zur Lösung

(x + 2) y^{'} (x) = 3 y

Solve separable ODE:

y = e^{c_{1}} x^{3} + 6 e^{c_{1}} x^{2} + 12 e^{c_{1}} x + 8 e^{c_{1}}

y = e^{c_{1}} x^{3} + 6 e^{c_{1}} x^{2} + 12 e^{c_{1}} x + 8 e^{c_{1}}

\frac{d y}{d x} = y^{2} \cdot x^{2}

y^{(5)} + 9 y^{^{'}} = 0

(1 + e^{x}) y \cdot y^{^{'}} = e^{x}

\frac{d y}{d x} = \frac{10 ( 1 + x )}{x y}

\frac{d x}{d t} + cos (t) x = cos (t)