4y^'-2e^{3x}y=0,y(0)=6

Lösung

4 y^{^{'}} - 2 e^{3 x} y = 0, y (0) = 6

y = 6 e^{\frac{e ^{3 x} - 1}{6}}

Schritte zur Lösung

4 y^{'} (x) - 2 e^{3 x} y = 0

Solve separable ODE:

y = 6 e^{\frac{e ^{3 x} - 1}{6}}

y = 6 e^{\frac{e ^{3 x} - 1}{6}}

cos^{2} (x) \frac{d y}{d x} = y + 3

y^{^{'}} + \frac{x}{2} y = x

y \frac{d y}{d x} = \frac{( x - e ^{x} )}{e ^{y^{2}}}

(2 x + 1) y^{^{'}} + y^{2} = 0

(2 x - 1) d x + (3 y + a) d y = 0