u^'=csc(\H(x))cos(x/2)

Lösung

u^{^{'}} = csc (H (x)) cos (\frac{x}{2})

u (x) = \int csc (H (x)) cos (\frac{x}{2}) d x

Schritte zur Lösung

u^{'} (x) = csc (H (x)) cos (\frac{x}{2})

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

u (x) = \int csc (H (x)) cos (\frac{x}{2}) d x

u (x) = \int csc (H (x)) cos (\frac{x}{2}) d x

\frac{d y}{d x} = - \frac{3}{2} y + \frac{1}{2} y^{2}

a d a + b d b = 0

y^{^{'}} = 5 y + 2

(x^{2} + 1) d x + \frac{1}{y} d y = 0

10 x^{2} y + 2 x^{3} y^{^{'}} - 16 y = 0