y^'= x/(5y)

Lösung

y^{^{'}} = \frac{x}{5 y}

y = \frac{x ^{2}}{5} + c_{1}, y = - \frac{x ^{2}}{5} + c_{1}

Schritte zur Lösung

y^{'} (x) = \frac{x}{5 y}

Solve separable ODE:

y = \frac{x ^{2}}{5} + c_{1}, y = - \frac{x ^{2}}{5} + c_{1}

y = \frac{x ^{2}}{5} + c_{1}, y = - \frac{x ^{2}}{5} + c_{1}

4 y^{^{'}} - 4 e^{2 x} y = 0, y (0) = 3

4 (1 + y^{2}) d x - x y d y = 0

\frac{d y}{d t} + y t sin (t) = 0

\frac{d y}{d x} = - \frac{7}{4} x^{8} y^{6}

y^{^{'}} = y tan (x) - x^{2} y