y^'-3ty=5t

Lösung

y^{^{'}} - 3 t y = 5 t

y = \frac{e ^{\frac{3 t ^{2} + c _{1}}{2}}}{3} - \frac{5}{3}

Schritte zur Lösung

y^{'} (t) - 3 t y = 5 t

Solve separable ODE:

y = \frac{e ^{\frac{3 t ^{2} + c _{1}}{2}}}{3} - \frac{5}{3}

y = \frac{e ^{\frac{3 t ^{2} + c _{1}}{2}}}{3} - \frac{5}{3}

x y^{^{'}} - 9 y^{2} = 0

x \cdot y^{^{'}} - 2 y \cdot ln (x) = 0

\frac{d y}{d x} = sin (x) e^{2 y}

\frac{d y}{d x} = x^{2} (y + 3)

2 y^{4} d x + 5 y^{3} x d y = 0