(x^2+1)dt=4txdx

Lösung

(x^{2} + 1) d t = 4 t x d x

t (x) = e^{c_{1}} x^{4} + 2 e^{c_{1}} x^{2} + e^{c_{1}}

Schritte zur Lösung

(x^{2} + 1) d t (x) = 4 t (x) x d x

Solve separable ODE:

t (x) = e^{c_{1}} x^{4} + 2 e^{c_{1}} x^{2} + e^{c_{1}}

t (x) = e^{c_{1}} x^{4} + 2 e^{c_{1}} x^{2} + e^{c_{1}}

\frac{d y}{d x} = \frac{e ^{2 x}}{cos ( 2 y )}

y^{^{'}} = - 2 x e^{y}, y (2) = 5

d y = x^{4} (1 - 5 y) d x

y^{^{'}} + y - 1 = 0

7 y y^{^{'}} = x, y (7) = 3