yy^'+x=0,y(0)=-2

Lösung

y y^{^{'}} + x = 0, y (0) = - 2

y = - - x^{2} + 4

Schritte zur Lösung

y y^{'} (x) + x = 0

Solve separable ODE:

y = - - x^{2} + 4

y = - - x^{2} + 4

y^{^{'}} - x y = 0, y (0) = 1, y (0) = 1

x^{^{'}} = \frac{1}{x}

y^{^{'}} = 2 y (1 - \frac{y}{6})

x^{^{'}} + 7 x = 0

\frac{d}{d x} (2 x y) - y^{2} = 1