2yy^'=9t^2,y(0)=8

Lösung

2 y y^{^{'}} = 9 t^{2}, y (0) = 8

y = 3 t^{3} + 64

Schritte zur Lösung

2 y y^{'} (t) = 9 t^{2}

Solve separable ODE:

y = 3 t^{3} + 64

y = 3 t^{3} + 64

y^{^{'}} = \frac{2 cos ( 2 x )}{3 + 2 y}

(y^{2} + y) - x \frac{d y}{d x} = 0

y^{^{'}} - 3 y^{^{'}} + 2 y = 0

\frac{d y}{d x} (3 x^{2} y) = 5 x^{2}

y^{^{'}} = 3 x^{2} (y^{2} + 16), y (0) = 0