dy+ytan(x)dx=0

Lösung

d y + y tan (x) d x = 0

y = c_{1} cos (x)

Schritte zur Lösung

d y + y tan (x) d x = 0

Solve separable ODE:

y = c_{1} cos (x)

y = c_{1} cos (x)

\frac{d y}{d x} = (x - 1)^{2} e^{y}

\frac{d y}{d x} + 2 y = e^{2}

(2 + t) y^{^{'}} + y = - 1

\frac{d y}{d x} 8 x^{2} - y^{2} = 6

x^{^{'}} = e^{x + t}