y^'=(3y)/(x+6)

Lösung

y^{^{'}} = \frac{3 y}{x + 6}

y = e^{c_{1}} x^{3} + 18 e^{c_{1}} x^{2} + 108 e^{c_{1}} x + 216 e^{c_{1}}

Schritte zur Lösung

y^{'} (x) = \frac{3 y}{x + 6}

Solve separable ODE:

y = e^{c_{1}} x^{3} + 18 e^{c_{1}} x^{2} + 108 e^{c_{1}} x + 216 e^{c_{1}}

y = e^{c_{1}} x^{3} + 18 e^{c_{1}} x^{2} + 108 e^{c_{1}} x + 216 e^{c_{1}}

x^{^{'}} = - x + 1

4 y x \frac{d x}{d y} = x^{2} + 1

(x^{2} - 3) y^{^{'}} = x (y^{2} + 16), y (2) = 4

\frac{d y}{d x} = 3 y^{2} - y^{2} sin (x)

\frac{d y}{d x} = 3 x e^{3 x + y}