What is the solution for xln(x)dy+yln(y)dx=0 ?

The solution for xln(x)dy+yln(y)dx=0 is y=e^{(c_{1})/(ln(x))}

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xln(x)dy+yln(y)dx=0

x ln (x) d y + y ln (y) d x = 0

y = e^{\frac{c _{1}}{l n ( x )}}

Solution steps

x ln (x) d y + y ln (y) d x = 0

Solve separable ODE:

y = e^{\frac{c _{1}}{l n ( x )}}

y = e^{\frac{c _{1}}{l n ( x )}}

y^{^{'}} + a \cdot y^{2} = - b

f^{^{'}} (t) = f (t)^{- 1}

y^{^{'}} = 2 x^{3} (1 + y^{2}), y (1) = 0

\frac{d x}{d t} = 8 (x^{2} + 1), x (\frac{π}{4}) = 1

\frac{d h}{d t} = - 0.03 h - 19

What is the solution for xln(x)dy+yln(y)dx=0 ?
The solution for xln(x)dy+yln(y)dx=0 is y=e^{(c_{1})/(ln(x))}