y*y^'=x

Lösung

y \cdot y^{^{'}} = x

y = x^{2} + c_{1}, y = - x^{2} + c_{1}

Schritte zur Lösung

y \cdot y^{'} (x) = x

Solve separable ODE:

y = x^{2} + c_{1}, y = - x^{2} + c_{1}

y = x^{2} + c_{1}, y = - x^{2} + c_{1}

\frac{d y}{d t} = y - y t^{2}

d t = \frac{200 d m}{1600 - 3 m}

\frac{d V}{d t} = 20 - \frac{5}{100} V

\frac{d y}{d x} = - \frac{6}{7} x^{7} y^{9}

\frac{x d y}{d x} - y - 1 = 0