(2x-6}{25}+(2(y-5)(\frac{dy)/(dx)))/9 =1

Lösung

\frac{2 x - 6}{25} + \frac{2 ( y - 5 ) ( \frac{d y}{d x} )}{9} = 1

y = \frac{25 + - 9 ( x ^{2} - 31 x - c _{1} ) + 625}{5}, y = \frac{25 - - 9 ( x ^{2} - 31 x - c _{1} ) + 625}{5}

Schritte zur Lösung

\frac{2 x - 6}{25} + \frac{2 ( y - 5 ) ( \frac{d y}{d x} )}{9} = 1

Solve separable ODE:

y = \frac{25 + - 9 ( x ^{2} - 31 x - c _{1} ) + 625}{5}, y = \frac{25 - - 9 ( x ^{2} - 31 x - c _{1} ) + 625}{5}

y = \frac{25 + - 9 ( x ^{2} - 31 x - c _{1} ) + 625}{5}, y = \frac{25 - - 9 ( x ^{2} - 31 x - c _{1} ) + 625}{5}

(x^{2} + 6 x^{2} y^{2}) d x + e^{x^{3}} y d y = 0

y^{\frac{9}{2}} \frac{d y}{d x} - y^{4} = - y^{\frac{11}{2}}

\frac{d y}{d x} = 18 + 30 x + 12 y + 20 x y

y^{^{'}} + 32 \frac{y}{x} = 0

y^{^{'}} = \frac{x y sin ( x )}{y + 1}, y (0) = 1