x^'+x^2=0

Lösung

x^{^{'}} + x^{2} = 0

x = - \frac{1}{- t + c _{1}}

Schritte zur Lösung

x^{'} (t) + x^{2} = 0

Solve separable ODE:

x = - \frac{1}{- t + c _{1}}

x = - \frac{1}{- t + c _{1}}

y^{^{'}} = \frac{24 ln ^{2} ( x )}{x e ^{y}}

\frac{d y}{d x} = \frac{150 - y}{200}

x^{^{'}} = 650 - x

e^{x} y^{^{'}} = y

\frac{d y}{d x} = - \frac{2 x y}{1 + x ^{2}}