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Beliebt Rechnen >

y^'= 1/(y^1)

Lösung

y^{^{'}} = \frac{1}{y ^{1}}

Lösung

y = 2 t + c_{1}, y = - 2 t + c_{1}

Schritte zur Lösung

y^{'} (t) = \frac{1}{y ^{1}}

Solve separable ODE:

y = 2 t + c_{1}, y = - 2 t + c_{1}

y = 2 t + c_{1}, y = - 2 t + c_{1}

Graph

Beliebte Beispiele

(dy)/(dx)=6(5-y)

\frac{d y}{d x} = 6 (5 - y)

(dy)/(dx)=(2y(2x-1)e^x)/(2x+1)

\frac{d y}{d x} = \frac{2 y ( 2 x - 1 ) e ^{x}}{2 x + 1}

y^'=1+4y^2,y(0)=0

y^{^{'}} = 1 + 4 y^{2}, y (0) = 0

y^'=((e^{-x}-e^x))/((3+4y))

y^{^{'}} = \frac{( e ^{- x} - e ^{x} )}{( 3 + 4 y )}

9ty+e^ty^'= y/(t^2+81)

9 t y + e^{t} y^{^{'}} = \frac{y}{t ^{2} + 81}